3 Chapter เคชเคขเคผเฅ‹ Selection เคชเค•เฅเค•เคพ ๐Ÿ‘ SSC MATHS BY GAGAN PRATAP SIR ๐Ÿ‘‘ #ssc #cgl #maths #selection
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YouTubeGagan Pratap Maths
3 Chapter เคชเคขเคผเฅ‹ Selection เคชเค•เฅเค•เคพ ๐Ÿ‘ SSC MATHS BY GAGAN PRATAP SIR ๐Ÿ‘‘ #ssc #cgl #maths #selection
SSC Maths เคฎเฅ‡เค‚ 45% Questions เคธเคฟเคฐเฅเคซ เค‡เคจ 3 Chapters เคธเฅ‡! | Gagan Pratap Sir ๐Ÿ˜ฑ เค•เฅเคฏเคพ เค†เคช เคœเคพเคจเคคเฅ‡ เคนเฅˆเค‚ เค•เคฟ SSC เค•เฅ‡ เคชเคฟเค›เคฒเฅ‡ เคตเคฐเฅเคทเฅ‹เค‚ เค•เฅ‡ Maths Questions เค•เคพ เคตเคฟเคถเฅเคฒเฅ‡เคทเคฃ เคฌเคคเคพเคคเคพ เคนเฅˆ เค•เคฟ เคฒเค—เคญเค— 45% เคชเฅเคฐเคถเฅเคจ เค•เฅ‡เคตเคฒ 3 Chapters ...
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YouTubeGagan Pratap Maths
Q) Find the domain of ๐‘(๐‘ฅ)=sin^(โˆ’1) (1โˆ’2๐‘ฅ^2 ). Hence,find the value of ๐‘ฅ for which p(๐‘ฅ)=๐œ‹/6.
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Q) Find the domain of ๐‘(๐‘ฅ)=sin^(โˆ’1) (1โˆ’2๐‘ฅ^2 ). Hence,find the value of ๐‘ฅ for which p(๐‘ฅ)=๐œ‹/6.
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